JEE MAIN - Physics (2019 - 12th April Morning Slot - No. 26)
A man (mass = 50 kg) and his son (mass = 20 kg) are standing on a frictionless surface facing each other. The
man pushes his son so that he starts moving at a speed of 0.70 ms–1 with respect to the man. The speed of the
man with respect to the surface is :
0.28 ms–1
0.47 ms–1
0.20 ms–1
0.14 ms–1
설명
50 V1 = 20 V2
V1 + V2 = 0.70
V1 = 0.20
V1 + V2 = 0.70
V1 = 0.20